Algebraic Solutions to Simultaneous Equations Worksheets
How to Transition Algebraic Solutions to Simultaneous Equations  Doing a simultaneous equation is a common method of finding the values of variables in a twovariable equation. To find the values of variables in a twovariable equation, you need to have two equations lying on the same plane. You cannot find the values of two variables of a single equation unless you have another equation that can be used to create a temporary value. Algebraic equations that are complicated and involve two variables can be shifted to simultaneous equations, all that is needed is another equation that compliments the other one and lies on the same plane. We write one equation in terms of a single variable, create its temporary value in terms of the other variable, and substitute its value in the other equation. Then after solving the equation for that variable whose temporary value we substituted in the other equation, We get the value of the other variable. Once we find the final value of any one of the variables, we can easily put it in any of the given equations to get the value of the other variable.

Basic Lesson
Demonstrates the use of cross algebra in simultaneous equations. Practice problems are provided. Subtract the second equation from the first and then insert the value of y into the equation and find the value of x.
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Intermediate Lesson
Explains how to reorder simultaneous equations. Practice problems are provided.
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Independent Practice 1
Contains 20 Algebraic Solutions to Simultaneous Equations problems. The answers can be found below.
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Independent Practice 2
Features another 20 Algebraic Solutions to Simultaneous Equations problems.
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Homework Worksheet
12 Algebraic Solutions to Simultaneous Equations problems for students to work on at home. Example problems are provided and explained.
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Topic Quiz
10 Algebraic Solutions to Simultaneous Equations problems. A math scoring matrix is included.
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How Many Bucks?
Amy gave Ann as many dollars as Ann started out with. Ann
gave Amy back as much as Amy had left. Amy then gave Ann back as many dollars
as Ann had left, which left Amy broke and gave Ann a total of $80. How much
did each start with?
Amy = 50, Ann = 30